I agree totally with Ricardo. But you have to look hard (and perhaps long!) at the C12 schematic to see that, although topologically different, the method is electrically the same as that used by the C24, or by the Aurycle tube mics.
http://www.aurycle.com/manual/a5500_schematic_clean.jpg
If you have two resistors in series with a d.c. voltage source, the voltage drop across any one resistor is the same whether it has one end connected to the +ve terminal of the source, or to the -ve terminal. Of course, the absolute voltages are different, but the resistor only sees the relative value from end to end. In the case of the tube, the potential difference between cathode and grid can be made exactly the same as in the original C12 circuit by adopting the method used in the C24 circuit. As with the resistor, the only thing that matters in the C12/C24 circuits is what the tube sees, not the absolute voltages.
I explained the configuration thus in an earlier thread:
Look carefully at the C12 circuit, particularly at the 1k resistor, R8. It is true that the cathode is connected directly to ground, but the grid resistor, R15 is not: it is connected to R11 and thence, via R10 to the negative end of R8. The other end of R8 is connected to ground. There is current passing through R8 -- actually the return from the HT or B+ line to the bottom end of the lower winding of the transfomer. This makes the left hand end of R8 negative with respect to ground. Thus the grid is also negative with respect to the cathode, as is normally achieved by means of a resistor in series with the cathode. (See the C24 circuit.) The method of achieving the bias is not unlike that in the U47 circuit which also relies a on a voltage across a resistor (R3) fixed by a larger current also flowing through it -- in that case the heater current.
The connection between R10 and R11 may be obscured if you are looking at the version of the C12 circuit on which someone has kindly drawn a fat vertical line with arrow heads on it. This one is cleaner:
http://www.groupdiy.com/index.php?action=dlattach;topic=44737.0;attach=8315
The method used in the C12 just places the resistor that would normally be connected between cathode and ground to the position of R8. See
http://www.hans-egebo.dk/Tutorial/biasing.htm, where it is described as "Power supply backoff".
David