Sorry to mingle myself in this, but as Samuel & John actually already said or implicated, whatever the o/l output impedance is, it gets reduced by a massive factor (essentially the open loop transfer of the opamp * ), since without much doubt you'll be using some kind of negative feedback. So while the above stated 200,000 ('=' 106dB) isn't available for all frequencies, it'll be clear that the resulting 'small-signal output impedance' is pretty small.
Unless there are series resistors added, following the closed loop structure... unless they're very small these will usually doninate/determine the driving source impedance that's seen by the TX.
Regards,
Peter
*: possibly reduced by an amount equal to the closed loop gain, too lazy/hot here to think about that now, but in either case you'll have at least a whopping 50...60dB reduction of that o/l value.